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mysql笔试题18道

部门表、员工表、薪水等级表

1.取得每个部门最高薪水人员名称

第一步:取得每个部门最高薪水作为临时表t 

select deptno,max(sal) as maxSal from emp group by deptno

第二步:临时表t与emp表连接条件 e.deptno=t.deptno and e.sal=t.maxSal 

select e.ename,t.* from emp e join (select deptno,max(sal) as maxSal from emp group by deptno order by deptno) t on e.deptno=t.deptno and e.sal=t.maxSal

2.哪些人的薪水在部门的平均薪水之上

第一步:取得每个部门平均薪水作为临时表t 

SELECT DEPTNO, AVG(SAL) FROM emp GROUP BY DEPTNO;

第二步:临时表t与emp表连接条件 e.deptno=t.deptno and e.sal>t.avgSal 

SELECT t.*,e.ENAME,e.SAL FROM emp e JOIN (SELECT DEPTNO, AVG(SAL) AS avgSal FROM emp GROUP BY DEPTNO) t ON e.DEPTNO=t.DEPTNO AND e.SAL>t.avgSal ORDER BY DEPTNO;

 

 3.取得部门中(所有人)平均的薪水等级

平均的薪水等级:先求出每个薪水对应的等级,然后找出薪水等级的平均值

平均薪水的等级:先求出每个部门的平均薪水,再根据平均薪水划分等级

SELECT e.ENAME,e.DEPTNO,e.SAL,s.GRADE FROM emp e JOIN salgrade s ON e.SAL BETWEEN s.LOSAL AND s.HISAL ORDER BY DEPTNO; SELECT e.DEPTNO,AVG(s.GRADE) FROM emp e JOIN salgrade s ON e.SAL BETWEEN s.LOSAL AND s.HISAL GROUP BY e.DEPTNO;

 

4. 不准用Max函数取得最高薪水(两种做法)

第一种方案:

SELECT ENAME,SAL FROM emp ORDER BY SAL DESC LIMIT 0,1;

第二种方案:表的自连接 

SELECT SAL FROM emp WHERE SAL NOT IN(SELECT DISTINCT a.SAL FROM emp a JOIN emp b ON a.SAL(SELECT MAX(SAL) FROM emp WHERE EMPNO NOT IN (SELECT DISTINCT MGR FROM emp WHERE MGR IS NOT NULL));

 

9.取出薪水最高的前5名员工(这里不需要考虑第6名与第5名工资一样的情况)

SELECT ENAME,SAL FROM emp ORDER BY SAL DESC LIMIT 5;

 

10.取出薪水最高的第六到第十名的员工 

SELECT ENAME,SAL FROM emp ORDER BY SAL DESC LIMIT 5,5;

 

11.取得最后入职的5名员工 

SELECT ENAME,HIREDATE FROM emp ORDER BY HIREDATE DESC LIMIT 5;

 

12.取得每个薪水等级有多少员工 

第一步:取出每个员工薪水对应的等级

SELECT e.ENAME,e.SAL,s.GRADE FROM emp e JOIN salgrade s ON e.SAL BETWEEN s.LOSAL AND s.HISAL;

 

第二步:根据其等级进行分组并计数

SELECT s.GRADE,COUNT(*) FROM emp e JOIN salgrade s ON e.SAL BETWEEN s.LOSAL AND s.HISAL GROUP BY s.GRADE;

 

 13.列出所有员工及其领导的名字

SELECT a.ENAME '员工',b.ENAME '领导' FROM emp a LEFT JOIN emp b ON a.MGR=b.EMPNO;

 

14.列出受雇日期早于其直接上级的所有员工的编号,姓名,部门名称 

SELECT a.EMPNO '员工号',a.ENAME '员工',a.HIREDATE,b.ENAME '领导',b.HIREDATE,d.DNAME '部门名称' FROM emp a JOIN emp b ON a.MGR=b.EMPNO JOIN dept d ON a.DEPTNO=d.DEPTNO WHERE a.HIREDATE=5;

 

17.列出薪资比“Smith”高的所有员工信息

SELECT ENAME,SAL FROM emp WHERE SAL >(SELECT SAL FROM emp WHERE ENAME='SMITH');

 

18.列出所有(“CLERK”)办事员的姓名及其部门名称,部门的人数 

第一步:列出所有(“CLERK”)办事员的姓名及其部门名称 临时表t1

SELECT e.ENAME,e.JOB,d.DNAME,d.DEPTNO FROM emp e JOIN dept d ON e.DEPTNO=d.DEPTNO WHERE e.JOB='CLERK';

 

第二步:列出部门的人数 临时表t2

SELECT DEPTNO,COUNT(*) FROM emp GROUP BY DEPTNO;

 

第三步:两张临时表连接

SELECT t1.*,t2.deptCount FROM (SELECT e.ENAME,e.JOB,d.DNAME,d.DEPTNO FROM emp e JOIN dept d ON e.DEPTNO=d.DEPTNO WHERE e.JOB='CLERK') t1 JOIN (SELECT DEPTNO,COUNT(*) AS deptCount FROM emp GROUP BY DEPTNO) t2 ON t1.DEPTNO=t2.DEPTNO;

 

 

 

 

 

 

 

 

 

 

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